# How many bales of straw cover an acre?

## How many bales of straw cover an acre?

When applied properly, approximately 20-40 percent of the original ground surface can be seen. The application rate per acre should be about 2 tons (or one 74 pound bale per 800 square feet). Straw should be clean rice, barley, or wheat straw.

## How much does 2 bales of hay cost?

The Price of Hay Bales By Weight

Hay Quality Bale Type Minimum Price Per Ton
Large Round \$70

How many square feet does a bale of Pinestraw cover?

35 to 45 square feet
A bale of pine straw covers about 35 to 45 square feet depending on the depth.

How many cubic feet does a bale of hay cover?

So, for example a 5 ft by 5 ft round bale contains about 98 cubic feet of hay compared to a 4 ft by 4 ft bale with about half that.

### How much is a bale of straw?

Straw prices were steady and there is a demand for straw. Small square bales averaged \$4.60 a bale (range of \$2.00 to \$6.00). Large square bale straw averaged \$64.00 per bale (a range of \$40.00 to \$90.00). Large round bale straw averaged \$58.00 per bale (a range of \$40.00 – \$85.00).

### How do you calculate mulch needed?

Keep in mind that mulch is sold by the cubic yard. One cubic yard of the material covers a 324-square-foot area an inch deep. So, to determine your total, multiply your square footage by the depth in inches desired, then divide by 324. Here’s your formula: Square footage x desired depth / 324 = cubic yards needed.

How much is a bale of Pinestraw?

A bale costs about \$45 to \$50, but Prezioso said the synthetic straw “pays for itself” in about 18 months when compared to organic pine straw usage. Good quality, long-leaf organic pine straw typically costs \$6 to \$7 a bale, Carvin said, and covers about 35-square feet per bale, Carvin said.

How much hay is in a 4×5 round bale?

Tables

Bale Size (ft) Est. Bale Weight 2 (lb) Hay Consumed per Cow per Day5 (lb)
4×5 800 26
4×6 1,153 26
5×5 1,000 26
5×6 1,441 26

## How do you calculate hay for cattle?

Determine the number of bales of hay that each cow needs by dividing the cow’s yearly need by the adjusted weight of each bale. For a cow needing 8,190 pounds of hay per year and a bale weight of 960 pounds, divide 8,190 by 960 for a yearly need of about 8.5 bales per cow.